Hi. I have a few cy8c4124pvi-432. If the Vdd (=Vccd) voltage exceeds 4.5 V they burn! What am I doing wrong? Please help!
without knowing your circuit it's hard to give help. Please post your circuit.
2 wires from power supply. 1st to Vdd and Vccd, 2nd to Vss. 4.55V = 3.6A and burn. (at 3.3V = 0A, chip works ok)
The part is rated at 6V absolute max. From the datasheet -
Unregulated External Supply
In this mode, the PSoC 4100 is powered by an External Power
Supply that can be anywhere in the range of 1.8 to 5.5 V. This
range is also designed for battery-powered operation, for
instance, the chip can be powered from a battery system that
starts at 3.5 V and works down to 1.8 V. In this mode, the internal
regulator of the PSoC 4100 supplies the internal logic and the
VCCD output of the PSoC 4100 must be bypassed to ground via
an external Capacitor (in the range of 1 to 1.6 µF; X5R ceramic
VDDA and VDDD must be shorted together; the grounds, VSSA
and VSS must also be shorted together. Bypass capacitors must
be used from VDDD to ground, typical practice for systems in this
frequency range is to use a capacitor in the 1 µF range in parallel
with a smaller capacitor (0.1 µF for example). Note that these are
simply rules of thumb and that, for critical applications, the PCB
layout, lead inductance, and the Bypass capacitor parasitic
should be simulated to design and obtain optimal bypassing.
An example of a bypass scheme for the 44-TQFP package
I think your VCCD should have been bypassed, as its an internally
I feel myself so stupid... Now it works fine. Thanks very much indeed!
Welcome to my club :), glad to have helped.
Aaaaah, sorry, I didn't think about the two power supply modes. My fault.