isr component directly detects rising edge. Is this idea going to be work?

	qingshanshan posted on 18 Mar 2013 10:37 AM PST Senior Member 16 Forum Posts

I would like to simplify my hardware design for raising 2 interrupts events with a single digital input pin to detect pulse edges. So my idea is to use digital input hardware pin to detect pulse falling edge while a isr component to detect a rising edge by connecting to the digital input pin. This trys to raise 2 seperated interrupt events. Make clear that it is not to raise a single event with detecting rising and falling edge. The topdesign is shown as following diagram. Is this going to work? Has anyone have any this experience?

Qingshan

Re: isr component directly detects rising edge. Is this idea going to be work?

	danaaknight posted on 18 Mar 2013 10:50 AM PST Top Contributor 1773 Forum Posts

Answered here -

www.cypress.com/

Regards, Dana.

Re: isr component directly detects rising edge. Is this idea going to be work?

	PSoC73 posted on 21 Mar 2013 10:36 PM PST Top Contributor 176 Forum Posts

Hi qing-san, Pin-direct isr(isrLick0_rise) and Pins isr(isrLick0), Of course both are working. ISR property only can select a rise-edge but to through an invert logic can be select fall-edge. Besides, Pins isr(isrLick0) can reduce interruption resources, One ISR for multi pins. [input] tab of PIns property can select rise and fall. I recommand use Pins ISR and select [derived] in ISR property. That is neat I think. To use Pins-ISR, need one notice. Have to ensure clearing ISR in ISR routine. [uint8 Pin_ClearInterrupt(void);] That is my experience and the article is here http://www.cypress.com/?app=forum&id=2232&rID=75317 Please refer bundle design. Happy Interruption..

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isr component directly detects rising edge. Is this idea going to be work?

Re: isr component directly detects rising edge. Is this idea going to be work?

Re: isr component directly detects rising edge. Is this idea going to be work?